3.88 \(\int \frac {(d+e x)^2 (a+b \log (c x^n))^2}{x^2} \, dx\)

Optimal. Leaf size=133 \[ -\frac {d^2 \left (a+b \log \left (c x^n\right )\right )^2}{x}-\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right )}{x}+\frac {2 d e \left (a+b \log \left (c x^n\right )\right )^3}{3 b n}+e^2 x \left (a+b \log \left (c x^n\right )\right )^2-2 a b e^2 n x-2 b^2 e^2 n x \log \left (c x^n\right )-\frac {2 b^2 d^2 n^2}{x}+2 b^2 e^2 n^2 x \]

[Out]

-2*b^2*d^2*n^2/x-2*a*b*e^2*n*x+2*b^2*e^2*n^2*x-2*b^2*e^2*n*x*ln(c*x^n)-2*b*d^2*n*(a+b*ln(c*x^n))/x-d^2*(a+b*ln
(c*x^n))^2/x+e^2*x*(a+b*ln(c*x^n))^2+2/3*d*e*(a+b*ln(c*x^n))^3/b/n

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Rubi [A]  time = 0.17, antiderivative size = 133, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.304, Rules used = {2353, 2296, 2295, 2305, 2304, 2302, 30} \[ -\frac {d^2 \left (a+b \log \left (c x^n\right )\right )^2}{x}-\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right )}{x}+\frac {2 d e \left (a+b \log \left (c x^n\right )\right )^3}{3 b n}+e^2 x \left (a+b \log \left (c x^n\right )\right )^2-2 a b e^2 n x-2 b^2 e^2 n x \log \left (c x^n\right )-\frac {2 b^2 d^2 n^2}{x}+2 b^2 e^2 n^2 x \]

Antiderivative was successfully verified.

[In]

Int[((d + e*x)^2*(a + b*Log[c*x^n])^2)/x^2,x]

[Out]

(-2*b^2*d^2*n^2)/x - 2*a*b*e^2*n*x + 2*b^2*e^2*n^2*x - 2*b^2*e^2*n*x*Log[c*x^n] - (2*b*d^2*n*(a + b*Log[c*x^n]
))/x - (d^2*(a + b*Log[c*x^n])^2)/x + e^2*x*(a + b*Log[c*x^n])^2 + (2*d*e*(a + b*Log[c*x^n])^3)/(3*b*n)

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 2295

Int[Log[(c_.)*(x_)^(n_.)], x_Symbol] :> Simp[x*Log[c*x^n], x] - Simp[n*x, x] /; FreeQ[{c, n}, x]

Rule 2296

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.), x_Symbol] :> Simp[x*(a + b*Log[c*x^n])^p, x] - Dist[b*n*p, In
t[(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{a, b, c, n}, x] && GtQ[p, 0] && IntegerQ[2*p]

Rule 2302

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/(x_), x_Symbol] :> Dist[1/(b*n), Subst[Int[x^p, x], x, a + b*L
og[c*x^n]], x] /; FreeQ[{a, b, c, n, p}, x]

Rule 2304

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*Log[c*x^
n]))/(d*(m + 1)), x] - Simp[(b*n*(d*x)^(m + 1))/(d*(m + 1)^2), x] /; FreeQ[{a, b, c, d, m, n}, x] && NeQ[m, -1
]

Rule 2305

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((d_.)*(x_))^(m_.), x_Symbol] :> Simp[((d*x)^(m + 1)*(a + b*Lo
g[c*x^n])^p)/(d*(m + 1)), x] - Dist[(b*n*p)/(m + 1), Int[(d*x)^m*(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{
a, b, c, d, m, n}, x] && NeQ[m, -1] && GtQ[p, 0]

Rule 2353

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*((f_.)*(x_))^(m_.)*((d_) + (e_.)*(x_)^(r_.))^(q_.), x_Symbol]
:> With[{u = ExpandIntegrand[(a + b*Log[c*x^n])^p, (f*x)^m*(d + e*x^r)^q, x]}, Int[u, x] /; SumQ[u]] /; FreeQ[
{a, b, c, d, e, f, m, n, p, q, r}, x] && IntegerQ[q] && (GtQ[q, 0] || (IGtQ[p, 0] && IntegerQ[m] && IntegerQ[r
]))

Rubi steps

\begin {align*} \int \frac {(d+e x)^2 \left (a+b \log \left (c x^n\right )\right )^2}{x^2} \, dx &=\int \left (e^2 \left (a+b \log \left (c x^n\right )\right )^2+\frac {d^2 \left (a+b \log \left (c x^n\right )\right )^2}{x^2}+\frac {2 d e \left (a+b \log \left (c x^n\right )\right )^2}{x}\right ) \, dx\\ &=d^2 \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x^2} \, dx+(2 d e) \int \frac {\left (a+b \log \left (c x^n\right )\right )^2}{x} \, dx+e^2 \int \left (a+b \log \left (c x^n\right )\right )^2 \, dx\\ &=-\frac {d^2 \left (a+b \log \left (c x^n\right )\right )^2}{x}+e^2 x \left (a+b \log \left (c x^n\right )\right )^2+\frac {(2 d e) \operatorname {Subst}\left (\int x^2 \, dx,x,a+b \log \left (c x^n\right )\right )}{b n}+\left (2 b d^2 n\right ) \int \frac {a+b \log \left (c x^n\right )}{x^2} \, dx-\left (2 b e^2 n\right ) \int \left (a+b \log \left (c x^n\right )\right ) \, dx\\ &=-\frac {2 b^2 d^2 n^2}{x}-2 a b e^2 n x-\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right )}{x}-\frac {d^2 \left (a+b \log \left (c x^n\right )\right )^2}{x}+e^2 x \left (a+b \log \left (c x^n\right )\right )^2+\frac {2 d e \left (a+b \log \left (c x^n\right )\right )^3}{3 b n}-\left (2 b^2 e^2 n\right ) \int \log \left (c x^n\right ) \, dx\\ &=-\frac {2 b^2 d^2 n^2}{x}-2 a b e^2 n x+2 b^2 e^2 n^2 x-2 b^2 e^2 n x \log \left (c x^n\right )-\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )\right )}{x}-\frac {d^2 \left (a+b \log \left (c x^n\right )\right )^2}{x}+e^2 x \left (a+b \log \left (c x^n\right )\right )^2+\frac {2 d e \left (a+b \log \left (c x^n\right )\right )^3}{3 b n}\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 107, normalized size = 0.80 \[ -\frac {d^2 \left (a+b \log \left (c x^n\right )\right )^2}{x}-\frac {2 b d^2 n \left (a+b \log \left (c x^n\right )+b n\right )}{x}+\frac {2 d e \left (a+b \log \left (c x^n\right )\right )^3}{3 b n}+e^2 x \left (a+b \log \left (c x^n\right )\right )^2-2 b e^2 n x \left (a+b \log \left (c x^n\right )-b n\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[((d + e*x)^2*(a + b*Log[c*x^n])^2)/x^2,x]

[Out]

-((d^2*(a + b*Log[c*x^n])^2)/x) + e^2*x*(a + b*Log[c*x^n])^2 + (2*d*e*(a + b*Log[c*x^n])^3)/(3*b*n) - 2*b*e^2*
n*x*(a - b*n + b*Log[c*x^n]) - (2*b*d^2*n*(a + b*n + b*Log[c*x^n]))/x

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fricas [B]  time = 0.61, size = 291, normalized size = 2.19 \[ \frac {2 \, b^{2} d e n^{2} x \log \relax (x)^{3} - 6 \, b^{2} d^{2} n^{2} - 6 \, a b d^{2} n - 3 \, a^{2} d^{2} + 3 \, {\left (2 \, b^{2} e^{2} n^{2} - 2 \, a b e^{2} n + a^{2} e^{2}\right )} x^{2} + 3 \, {\left (b^{2} e^{2} x^{2} - b^{2} d^{2}\right )} \log \relax (c)^{2} + 3 \, {\left (b^{2} e^{2} n^{2} x^{2} + 2 \, b^{2} d e n x \log \relax (c) - b^{2} d^{2} n^{2} + 2 \, a b d e n x\right )} \log \relax (x)^{2} - 6 \, {\left (b^{2} d^{2} n + a b d^{2} + {\left (b^{2} e^{2} n - a b e^{2}\right )} x^{2}\right )} \log \relax (c) + 6 \, {\left (b^{2} d e x \log \relax (c)^{2} - b^{2} d^{2} n^{2} - a b d^{2} n + a^{2} d e x - {\left (b^{2} e^{2} n^{2} - a b e^{2} n\right )} x^{2} + {\left (b^{2} e^{2} n x^{2} - b^{2} d^{2} n + 2 \, a b d e x\right )} \log \relax (c)\right )} \log \relax (x)}{3 \, x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^2*(a+b*log(c*x^n))^2/x^2,x, algorithm="fricas")

[Out]

1/3*(2*b^2*d*e*n^2*x*log(x)^3 - 6*b^2*d^2*n^2 - 6*a*b*d^2*n - 3*a^2*d^2 + 3*(2*b^2*e^2*n^2 - 2*a*b*e^2*n + a^2
*e^2)*x^2 + 3*(b^2*e^2*x^2 - b^2*d^2)*log(c)^2 + 3*(b^2*e^2*n^2*x^2 + 2*b^2*d*e*n*x*log(c) - b^2*d^2*n^2 + 2*a
*b*d*e*n*x)*log(x)^2 - 6*(b^2*d^2*n + a*b*d^2 + (b^2*e^2*n - a*b*e^2)*x^2)*log(c) + 6*(b^2*d*e*x*log(c)^2 - b^
2*d^2*n^2 - a*b*d^2*n + a^2*d*e*x - (b^2*e^2*n^2 - a*b*e^2*n)*x^2 + (b^2*e^2*n*x^2 - b^2*d^2*n + 2*a*b*d*e*x)*
log(c))*log(x))/x

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giac [B]  time = 0.40, size = 329, normalized size = 2.47 \[ \frac {2 \, b^{2} d n^{2} x e \log \relax (x)^{3} + 3 \, b^{2} n^{2} x^{2} e^{2} \log \relax (x)^{2} + 6 \, b^{2} d n x e \log \relax (c) \log \relax (x)^{2} - 6 \, b^{2} n^{2} x^{2} e^{2} \log \relax (x) + 6 \, b^{2} n x^{2} e^{2} \log \relax (c) \log \relax (x) + 6 \, b^{2} d x e \log \relax (c)^{2} \log \relax (x) - 3 \, b^{2} d^{2} n^{2} \log \relax (x)^{2} + 6 \, a b d n x e \log \relax (x)^{2} + 6 \, b^{2} n^{2} x^{2} e^{2} - 6 \, b^{2} n x^{2} e^{2} \log \relax (c) + 3 \, b^{2} x^{2} e^{2} \log \relax (c)^{2} - 6 \, b^{2} d^{2} n^{2} \log \relax (x) + 6 \, a b n x^{2} e^{2} \log \relax (x) - 6 \, b^{2} d^{2} n \log \relax (c) \log \relax (x) + 12 \, a b d x e \log \relax (c) \log \relax (x) - 6 \, b^{2} d^{2} n^{2} - 6 \, a b n x^{2} e^{2} - 6 \, b^{2} d^{2} n \log \relax (c) + 6 \, a b x^{2} e^{2} \log \relax (c) - 3 \, b^{2} d^{2} \log \relax (c)^{2} - 6 \, a b d^{2} n \log \relax (x) + 6 \, a^{2} d x e \log \relax (x) - 6 \, a b d^{2} n + 3 \, a^{2} x^{2} e^{2} - 6 \, a b d^{2} \log \relax (c) - 3 \, a^{2} d^{2}}{3 \, x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^2*(a+b*log(c*x^n))^2/x^2,x, algorithm="giac")

[Out]

1/3*(2*b^2*d*n^2*x*e*log(x)^3 + 3*b^2*n^2*x^2*e^2*log(x)^2 + 6*b^2*d*n*x*e*log(c)*log(x)^2 - 6*b^2*n^2*x^2*e^2
*log(x) + 6*b^2*n*x^2*e^2*log(c)*log(x) + 6*b^2*d*x*e*log(c)^2*log(x) - 3*b^2*d^2*n^2*log(x)^2 + 6*a*b*d*n*x*e
*log(x)^2 + 6*b^2*n^2*x^2*e^2 - 6*b^2*n*x^2*e^2*log(c) + 3*b^2*x^2*e^2*log(c)^2 - 6*b^2*d^2*n^2*log(x) + 6*a*b
*n*x^2*e^2*log(x) - 6*b^2*d^2*n*log(c)*log(x) + 12*a*b*d*x*e*log(c)*log(x) - 6*b^2*d^2*n^2 - 6*a*b*n*x^2*e^2 -
6*b^2*d^2*n*log(c) + 6*a*b*x^2*e^2*log(c) - 3*b^2*d^2*log(c)^2 - 6*a*b*d^2*n*log(x) + 6*a^2*d*x*e*log(x) - 6*
a*b*d^2*n + 3*a^2*x^2*e^2 - 6*a*b*d^2*log(c) - 3*a^2*d^2)/x

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maple [C]  time = 0.56, size = 2521, normalized size = 18.95 \[ \text {Expression too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^2*(b*ln(c*x^n)+a)^2/x^2,x)

[Out]

-b^2*(-2*d*e*x*ln(x)-e^2*x^2+d^2)/x*ln(x^n)^2-b*(I*Pi*b*e^2*x^2*csgn(I*c*x^n)^3+2*I*ln(x)*Pi*b*d*e*csgn(I*x^n)
*csgn(I*c*x^n)*csgn(I*c)*x+2*I*ln(x)*Pi*b*d*e*csgn(I*c*x^n)^3*x-I*Pi*b*d^2*csgn(I*c*x^n)^3-I*Pi*b*e^2*x^2*csgn
(I*x^n)*csgn(I*c*x^n)^2+I*Pi*b*d^2*csgn(I*x^n)*csgn(I*c*x^n)^2+I*Pi*b*e^2*x^2*csgn(I*x^n)*csgn(I*c*x^n)*csgn(I
*c)-2*I*ln(x)*Pi*b*d*e*csgn(I*x^n)*csgn(I*c*x^n)^2*x+I*Pi*b*d^2*csgn(I*c*x^n)^2*csgn(I*c)-I*Pi*b*d^2*csgn(I*x^
n)*csgn(I*c*x^n)*csgn(I*c)-I*Pi*b*e^2*x^2*csgn(I*c*x^n)^2*csgn(I*c)-2*I*ln(x)*Pi*b*d*e*csgn(I*c*x^n)^2*csgn(I*
c)*x+2*b*d*e*n*x*ln(x)^2-4*b*d*e*x*ln(c)*ln(x)-2*b*e^2*x^2*ln(c)+2*b*e^2*n*x^2-4*a*d*e*x*ln(x)-2*a*e^2*x^2+2*b
*d^2*ln(c)+2*b*d^2*n+2*a*d^2)/x*ln(x^n)+1/12*(12*b^2*e^2*x^2*ln(c)^2-6*ln(x)*Pi^2*b^2*d*e*csgn(I*x^n)^2*csgn(I
*c*x^n)^4*x-12*a^2*d^2-12*ln(c)^2*b^2*d^2-24*b^2*d^2*n^2+3*Pi^2*b^2*d^2*csgn(I*c*x^n)^6-24*ln(c)*a*b*d^2-24*ln
(c)*b^2*d^2*n+12*a^2*e^2*x^2-24*a*b*n*d^2-24*a*b*e^2*n*x^2+24*I*ln(x)*ln(c)*Pi*b^2*d*e*csgn(I*x^n)*csgn(I*c*x^
n)^2*x+24*I*ln(x)*ln(c)*Pi*b^2*d*e*csgn(I*c*x^n)^2*csgn(I*c)*x+24*I*ln(x)*Pi*a*b*d*e*csgn(I*x^n)*csgn(I*c*x^n)
^2*x+24*ln(x)*a^2*d*e*x+24*a*b*e^2*x^2*ln(c)-24*b^2*e^2*n*x^2*ln(c)-24*I*ln(x)*ln(c)*Pi*b^2*d*e*csgn(I*c*x^n)^
3*x-24*I*ln(x)*Pi*a*b*d*e*csgn(I*c*x^n)^3*x+12*I*Pi*b^2*d*e*n*csgn(I*c*x^n)^3*ln(x)^2*x+12*I*n*Pi*b^2*e^2*x^2*
csgn(I*x^n)*csgn(I*c*x^n)*csgn(I*c)-24*I*ln(x)*ln(c)*Pi*b^2*d*e*csgn(I*x^n)*csgn(I*c*x^n)*csgn(I*c)*x-12*I*Pi*
a*b*d^2*csgn(I*x^n)*csgn(I*c*x^n)^2-12*I*Pi*a*b*d^2*csgn(I*c*x^n)^2*csgn(I*c)+12*I*Pi*ln(c)*b^2*e^2*x^2*csgn(I
*c*x^n)^2*csgn(I*c)+12*I*Pi*a*b*e^2*x^2*csgn(I*x^n)*csgn(I*c*x^n)^2+6*Pi^2*b^2*e^2*x^2*csgn(I*c)*csgn(I*x^n)^2
*csgn(I*c*x^n)^3+24*I*ln(x)*Pi*a*b*d*e*csgn(I*c*x^n)^2*csgn(I*c)*x-12*I*Pi*b^2*d*e*n*csgn(I*x^n)*csgn(I*c*x^n)
^2*ln(x)^2*x+12*I*ln(c)*Pi*b^2*d^2*csgn(I*c*x^n)^3+12*I*Pi*a*b*d^2*csgn(I*c*x^n)^3+12*I*Pi*b^2*d^2*n*csgn(I*c*
x^n)^3-6*Pi^2*b^2*d^2*csgn(I*x^n)^2*csgn(I*c*x^n)^3*csgn(I*c)+48*ln(x)*ln(c)*a*b*d*e*x-24*a*b*d*e*n*ln(x)^2*x-
24*ln(c)*b^2*d*e*n*ln(x)^2*x-24*I*ln(x)*Pi*a*b*d*e*csgn(I*x^n)*csgn(I*c*x^n)*csgn(I*c)*x+12*I*Pi*b^2*d*e*n*csg
n(I*x^n)*csgn(I*c*x^n)*csgn(I*c)*ln(x)^2*x+24*ln(x)*ln(c)^2*b^2*d*e*x+8*b^2*d*e*n^2*ln(x)^3*x+24*b^2*e^2*n^2*x
^2-12*I*Pi*a*b*e^2*x^2*csgn(I*x^n)*csgn(I*c*x^n)*csgn(I*c)-12*I*Pi*b^2*d*e*n*csgn(I*c*x^n)^2*csgn(I*c)*ln(x)^2
*x-3*Pi^2*b^2*e^2*x^2*csgn(I*c)^2*csgn(I*x^n)^2*csgn(I*c*x^n)^2-12*Pi^2*b^2*e^2*x^2*csgn(I*c)*csgn(I*x^n)*csgn
(I*c*x^n)^4+6*Pi^2*b^2*e^2*x^2*csgn(I*c)^2*csgn(I*x^n)*csgn(I*c*x^n)^3-12*I*Pi*ln(c)*b^2*e^2*x^2*csgn(I*x^n)*c
sgn(I*c*x^n)*csgn(I*c)+12*ln(x)*Pi^2*b^2*d*e*csgn(I*x^n)^2*csgn(I*c*x^n)^3*csgn(I*c)*x-6*ln(x)*Pi^2*b^2*d*e*cs
gn(I*x^n)^2*csgn(I*c*x^n)^2*csgn(I*c)^2*x-24*ln(x)*Pi^2*b^2*d*e*csgn(I*x^n)*csgn(I*c*x^n)^4*csgn(I*c)*x+12*ln(
x)*Pi^2*b^2*d*e*csgn(I*x^n)*csgn(I*c*x^n)^3*csgn(I*c)^2*x-12*I*ln(c)*Pi*b^2*d^2*csgn(I*x^n)*csgn(I*c*x^n)^2-12
*I*ln(c)*Pi*b^2*d^2*csgn(I*c*x^n)^2*csgn(I*c)-12*I*Pi*b^2*d^2*n*csgn(I*x^n)*csgn(I*c*x^n)^2+12*Pi^2*b^2*d^2*cs
gn(I*x^n)*csgn(I*c*x^n)^4*csgn(I*c)-6*Pi^2*b^2*d^2*csgn(I*x^n)*csgn(I*c*x^n)^3*csgn(I*c)^2+3*Pi^2*b^2*d^2*csgn
(I*x^n)^2*csgn(I*c*x^n)^4-6*Pi^2*b^2*d^2*csgn(I*x^n)*csgn(I*c*x^n)^5-6*Pi^2*b^2*d^2*csgn(I*c*x^n)^5*csgn(I*c)+
3*Pi^2*b^2*d^2*csgn(I*c*x^n)^4*csgn(I*c)^2-3*Pi^2*b^2*e^2*x^2*csgn(I*c*x^n)^6-6*ln(x)*Pi^2*b^2*d*e*csgn(I*c*x^
n)^6*x+12*I*n*Pi*b^2*e^2*x^2*csgn(I*c*x^n)^3-12*I*Pi*ln(c)*b^2*e^2*x^2*csgn(I*c*x^n)^3-12*I*Pi*a*b*e^2*x^2*csg
n(I*c*x^n)^3-12*I*Pi*b^2*d^2*n*csgn(I*c*x^n)^2*csgn(I*c)+3*Pi^2*b^2*d^2*csgn(I*x^n)^2*csgn(I*c*x^n)^2*csgn(I*c
)^2-3*Pi^2*b^2*e^2*x^2*csgn(I*x^n)^2*csgn(I*c*x^n)^4+6*Pi^2*b^2*e^2*x^2*csgn(I*x^n)*csgn(I*c*x^n)^5+6*Pi^2*b^2
*e^2*x^2*csgn(I*c)*csgn(I*c*x^n)^5-3*Pi^2*b^2*e^2*x^2*csgn(I*c)^2*csgn(I*c*x^n)^4+12*ln(x)*Pi^2*b^2*d*e*csgn(I
*x^n)*csgn(I*c*x^n)^5*x+12*ln(x)*Pi^2*b^2*d*e*csgn(I*c*x^n)^5*csgn(I*c)*x-6*ln(x)*Pi^2*b^2*d*e*csgn(I*c*x^n)^4
*csgn(I*c)^2*x+12*I*ln(c)*Pi*b^2*d^2*csgn(I*x^n)*csgn(I*c*x^n)*csgn(I*c)+12*I*Pi*a*b*d^2*csgn(I*x^n)*csgn(I*c*
x^n)*csgn(I*c)+12*I*Pi*b^2*d^2*n*csgn(I*x^n)*csgn(I*c*x^n)*csgn(I*c)+12*I*Pi*a*b*e^2*x^2*csgn(I*c*x^n)^2*csgn(
I*c)-12*I*n*Pi*b^2*e^2*x^2*csgn(I*x^n)*csgn(I*c*x^n)^2-12*I*n*Pi*b^2*e^2*x^2*csgn(I*c*x^n)^2*csgn(I*c)+12*I*Pi
*ln(c)*b^2*e^2*x^2*csgn(I*x^n)*csgn(I*c*x^n)^2)/x

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maxima [A]  time = 0.63, size = 200, normalized size = 1.50 \[ b^{2} e^{2} x \log \left (c x^{n}\right )^{2} - 2 \, a b e^{2} n x + 2 \, a b e^{2} x \log \left (c x^{n}\right ) + \frac {2 \, b^{2} d e \log \left (c x^{n}\right )^{3}}{3 \, n} + 2 \, {\left (n^{2} x - n x \log \left (c x^{n}\right )\right )} b^{2} e^{2} - 2 \, b^{2} d^{2} {\left (\frac {n^{2}}{x} + \frac {n \log \left (c x^{n}\right )}{x}\right )} + a^{2} e^{2} x + \frac {2 \, a b d e \log \left (c x^{n}\right )^{2}}{n} - \frac {b^{2} d^{2} \log \left (c x^{n}\right )^{2}}{x} + 2 \, a^{2} d e \log \relax (x) - \frac {2 \, a b d^{2} n}{x} - \frac {2 \, a b d^{2} \log \left (c x^{n}\right )}{x} - \frac {a^{2} d^{2}}{x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^2*(a+b*log(c*x^n))^2/x^2,x, algorithm="maxima")

[Out]

b^2*e^2*x*log(c*x^n)^2 - 2*a*b*e^2*n*x + 2*a*b*e^2*x*log(c*x^n) + 2/3*b^2*d*e*log(c*x^n)^3/n + 2*(n^2*x - n*x*
log(c*x^n))*b^2*e^2 - 2*b^2*d^2*(n^2/x + n*log(c*x^n)/x) + a^2*e^2*x + 2*a*b*d*e*log(c*x^n)^2/n - b^2*d^2*log(
c*x^n)^2/x + 2*a^2*d*e*log(x) - 2*a*b*d^2*n/x - 2*a*b*d^2*log(c*x^n)/x - a^2*d^2/x

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mupad [B]  time = 3.74, size = 228, normalized size = 1.71 \[ \ln \relax (x)\,\left (2\,d\,e\,a^2+4\,d\,e\,a\,b\,n+4\,d\,e\,b^2\,n^2\right )-\frac {a^2\,d^2+2\,a\,b\,d^2\,n+2\,b^2\,d^2\,n^2}{x}-\ln \left (c\,x^n\right )\,\left (\frac {2\,b\,\left (a+b\,n\right )\,d^2+4\,b\,\left (a+b\,n\right )\,d\,e\,x+2\,b\,\left (a-b\,n\right )\,e^2\,x^2}{x}-4\,b\,e^2\,x\,\left (a-b\,n\right )\right )+{\ln \left (c\,x^n\right )}^2\,\left (2\,b^2\,e^2\,x-\frac {b^2\,d^2+2\,b^2\,d\,e\,x+b^2\,e^2\,x^2}{x}+\frac {2\,b\,d\,e\,\left (a+b\,n\right )}{n}\right )+e^2\,x\,\left (a^2-2\,a\,b\,n+2\,b^2\,n^2\right )+\frac {2\,b^2\,d\,e\,{\ln \left (c\,x^n\right )}^3}{3\,n} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*log(c*x^n))^2*(d + e*x)^2)/x^2,x)

[Out]

log(x)*(2*a^2*d*e + 4*b^2*d*e*n^2 + 4*a*b*d*e*n) - (a^2*d^2 + 2*b^2*d^2*n^2 + 2*a*b*d^2*n)/x - log(c*x^n)*((2*
b*d^2*(a + b*n) + 2*b*e^2*x^2*(a - b*n) + 4*b*d*e*x*(a + b*n))/x - 4*b*e^2*x*(a - b*n)) + log(c*x^n)^2*(2*b^2*
e^2*x - (b^2*d^2 + b^2*e^2*x^2 + 2*b^2*d*e*x)/x + (2*b*d*e*(a + b*n))/n) + e^2*x*(a^2 + 2*b^2*n^2 - 2*a*b*n) +
(2*b^2*d*e*log(c*x^n)^3)/(3*n)

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sympy [B]  time = 2.06, size = 384, normalized size = 2.89 \[ - \frac {a^{2} d^{2}}{x} + 2 a^{2} d e \log {\relax (x )} + a^{2} e^{2} x - \frac {2 a b d^{2} n \log {\relax (x )}}{x} - \frac {2 a b d^{2} n}{x} - \frac {2 a b d^{2} \log {\relax (c )}}{x} + 2 a b d e n \log {\relax (x )}^{2} + 4 a b d e \log {\relax (c )} \log {\relax (x )} + 2 a b e^{2} n x \log {\relax (x )} - 2 a b e^{2} n x + 2 a b e^{2} x \log {\relax (c )} - \frac {b^{2} d^{2} n^{2} \log {\relax (x )}^{2}}{x} - \frac {2 b^{2} d^{2} n^{2} \log {\relax (x )}}{x} - \frac {2 b^{2} d^{2} n^{2}}{x} - \frac {2 b^{2} d^{2} n \log {\relax (c )} \log {\relax (x )}}{x} - \frac {2 b^{2} d^{2} n \log {\relax (c )}}{x} - \frac {b^{2} d^{2} \log {\relax (c )}^{2}}{x} + \frac {2 b^{2} d e n^{2} \log {\relax (x )}^{3}}{3} + 2 b^{2} d e n \log {\relax (c )} \log {\relax (x )}^{2} + 2 b^{2} d e \log {\relax (c )}^{2} \log {\relax (x )} + b^{2} e^{2} n^{2} x \log {\relax (x )}^{2} - 2 b^{2} e^{2} n^{2} x \log {\relax (x )} + 2 b^{2} e^{2} n^{2} x + 2 b^{2} e^{2} n x \log {\relax (c )} \log {\relax (x )} - 2 b^{2} e^{2} n x \log {\relax (c )} + b^{2} e^{2} x \log {\relax (c )}^{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**2*(a+b*ln(c*x**n))**2/x**2,x)

[Out]

-a**2*d**2/x + 2*a**2*d*e*log(x) + a**2*e**2*x - 2*a*b*d**2*n*log(x)/x - 2*a*b*d**2*n/x - 2*a*b*d**2*log(c)/x
+ 2*a*b*d*e*n*log(x)**2 + 4*a*b*d*e*log(c)*log(x) + 2*a*b*e**2*n*x*log(x) - 2*a*b*e**2*n*x + 2*a*b*e**2*x*log(
c) - b**2*d**2*n**2*log(x)**2/x - 2*b**2*d**2*n**2*log(x)/x - 2*b**2*d**2*n**2/x - 2*b**2*d**2*n*log(c)*log(x)
/x - 2*b**2*d**2*n*log(c)/x - b**2*d**2*log(c)**2/x + 2*b**2*d*e*n**2*log(x)**3/3 + 2*b**2*d*e*n*log(c)*log(x)
**2 + 2*b**2*d*e*log(c)**2*log(x) + b**2*e**2*n**2*x*log(x)**2 - 2*b**2*e**2*n**2*x*log(x) + 2*b**2*e**2*n**2*
x + 2*b**2*e**2*n*x*log(c)*log(x) - 2*b**2*e**2*n*x*log(c) + b**2*e**2*x*log(c)**2

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